
Appendix B: Equipment and Instrument Circuits
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The next step is to relate line currents to phase current
Substituting in for the currents
* *
1
* *
2
Re Re
Re Re
Summing the wattmeter readings results in
* * * *
1 2
Re Re Re Re
Since
then
1 2
Re Re Re
Finally, noting that
* * *
1 2
Re Re Re
ab ab ac ac cb cb ab ac cb
results in an expression that is the sum of the real power dissipated in each phase. A similar ar-
gument can be made for a wye-connected load.
As an example, calculate the expected reading of each wattmeter if the line-to-line voltage is
208 V for a balanced load and the load impedance Z = 8.0+j6.0 Ohms. The load impedance in
polar form is:
2 2
36.9
Z
Z
The phase ab current is given by
208 0
ab
ab
V
and the phase a current is given by
a ab
I I
with a phase c current for a balanced load of
c a
I I
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