BK Precision 4011A Instrucciones de operaciones Pagina 58

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Appendix B: Equipment and Instrument Circuits
201046
The next step is to relate line currents to phase current
a ab ac
c ca cb
I I I
I I I
Substituting in for the currents
* *
1
* *
2
Re Re
Re Re
ab ab ab ac
cb ca cb cb
W V I V I
W V I V I
Summing the wattmeter readings results in
* * * *
1 2
Re Re Re Re
ab ab ab ac cb ca cb cb
W W V I V I V I V I
Since
* *
ac ca
I I
then
* * *
1 2
Re Re Re
ab ab ab cb ac cb cb
W W V I V V I V I
Finally, noting that
ab cb ac
V V V
* * *
1 2
Re Re Re
ab ab ac ac cb cb ab ac cb
W W V I V I V I P P P
results in an expression that is the sum of the real power dissipated in each phase. A similar ar-
gument can be made for a wye-connected load.
As an example, calculate the expected reading of each wattmeter if the line-to-line voltage is
208 V for a balanced load and the load impedance Z = 8.0+j6.0 Ohms. The load impedance in
polar form is:
2 2
8 6 10
36.9
Z
Z
The phase ab current is given by
208 0
20.8 36.9
10 36.9
ab
ab
V
I A
Z
and the phase a current is given by
3 30 36.0 66.9
a ab
I I
with a phase c current for a balanced load of
120 36.0 53.1
c a
I I
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